# How do you write the Vertex form equation of the parabola x = y^2 - 4y + 20?

Rewrite it as ${\left(y - 2\right)}^{2} = x - 16$
This equation represents a horizontal parabola with its vertex at (16,2). The function would be either $y = + \sqrt{x - 16} + 2$ or $y = - \sqrt{x - 16} + 2$ representing top half and lower half respectively.