Question

How do you write the Vertex form equation of the parabola `x = y^2 - 4y + 20`?

Answer 1

Explained below.

Explanation:

Rewrite it as `(y-2)^2 = x-16`

This equation represents a horizontal parabola with its vertex at (16,2). The function would be either `y=+ sqrt (x-16) +2` or `y= - sqrt (x-16) +2` representing top half and lower half respectively.