Question

How do you write the vertex form equation of the parabola `y = 2x ^2 - 12x + 19`?

Answer 1

`y=2(x-3)^2+1`

Explanation:

Comparing with the general form `ax^2+bx+c` we get here a=2 ; b=-12; c=19 . we know x co-ordinate of vertex `=-b/(2*a) or 12/4=3` Putting x=3 on the equation we get `y=2.3^2-12*3+19=18-36+19=1`
So the co-ordinate of the Vertex is `(3,1)` So theVertex form of equation is `y=2(x-3)^2+1`graph{2x^2-12x+19 [-10, 10, -5, 5]}[Answer]