# How do you write the vertex form equation of the parabola y = 2x ^2 - 12x + 19?

$y = 2 {\left(x - 3\right)}^{2} + 1$
Comparing with the general form $a {x}^{2} + b x + c$ we get here a=2 ; b=-12; c=19 . we know x co-ordinate of vertex $= - \frac{b}{2 \cdot a} \mathmr{and} \frac{12}{4} = 3$ Putting x=3 on the equation we get $y = {2.3}^{2} - 12 \cdot 3 + 19 = 18 - 36 + 19 = 1$
So the co-ordinate of the Vertex is $\left(3 , 1\right)$ So theVertex form of equation is $y = 2 {\left(x - 3\right)}^{2} + 1$graph{2x^2-12x+19 [-10, 10, -5, 5]}[Answer]