Question

How do you write the vertex form equation of the parabola `y=x^2+6`?

Answer 1

`y=(x-0)^2+6=x^2+6`

Explanation:

`"the equation of a parabola in "color(blue)"vertex form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))`

`"where "(h,k)" are the coordinates of the vertex and a is"`
`"a multiplier"`

`y=x^2+6" is in this form"`

`"that is "y=(x-0)^2+6larrcolor(red)"in vertex form"`

`"with vertex "=(0,6)`
graph{x^2+6 [-20, 20, -10, 10]}