# How do you write  y= - 0.05x^2 + 12.8 into vertex form?

Jun 17, 2015

It is nearly in vertex form already, but you could write:

$y = - 0.05 {\left(x - 0\right)}^{2} + 12.8$

The vertex is at $\left(0 , 12.8\right)$

#### Explanation:

Vertex form is:

$y = a {\left(x - {x}_{0}\right)}^{2} + {y}_{0}$

where $a$ is some non-zero constant (positive or negative) and $\left({x}_{0} , {y}_{0}\right)$ is the vertex.