How do you write #y + 10 = 3(x - 1)^2# in standard form?

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Answer 1 · 2018-03-28T01:13:23

#y=3x^2-6x-7#

Given:

#y+10=3(x-1)^2#

Subtract #10# from both sides.

#y=3(x-1)^2-10#

Rewrite #(x-1)^2# as #(x-1)(x-1)#.

#y=3(x-1)(x-1)-10#

#y=3(x^2-2x+1)-10#

Distribute the #3# to the trinomial.

#y=3x^2-6x+3-10#

Simplify.

#y=3x^2-6x-7#