# How do you write y + 10 = 3(x - 1)^2 in standard form?

Mar 28, 2018

$y = 3 {x}^{2} - 6 x - 7$

#### Explanation:

Given:

$y + 10 = 3 {\left(x - 1\right)}^{2}$

Subtract $10$ from both sides.

$y = 3 {\left(x - 1\right)}^{2} - 10$

Rewrite ${\left(x - 1\right)}^{2}$ as $\left(x - 1\right) \left(x - 1\right)$.

$y = 3 \left(x - 1\right) \left(x - 1\right) - 10$

FOIL $\left(x - 1\right) \left(x - 1\right)$.
https://www.mathsisfun.com/definitions/foil-method.html

$y = 3 \left({x}^{2} - 2 x + 1\right) - 10$

Distribute the $3$ to the trinomial.

$y = 3 {x}^{2} - 6 x + 3 - 10$

Simplify.

$y = 3 {x}^{2} - 6 x - 7$