# How do you write y-11=3(x+4) in slope intercept form?

Feb 5, 2017

$y = \textcolor{red}{3} x + \textcolor{b l u e}{23}$

#### Explanation:

The slope-intercept form of a linear equation is: $y = \textcolor{red}{m} x + \textcolor{b l u e}{b}$

Where $\textcolor{red}{m}$ is the slope and $\textcolor{b l u e}{b}$ is the y-intercept value.

We can transform this equation to slope-intercept form by solving for $y$:

$y - 11 = 3 \left(x + 4\right)$

$y - 11 = \left(3 \times x\right) + \left(3 \times 4\right)$

$y - 11 = 3 x + 12$

$y - 11 + \textcolor{red}{11} = 3 x + 12 + \textcolor{red}{11}$

$y - 0 = 3 x + 23$

$y = 3 x + 23$