How do you write y11=3(x+4) in slope intercept form?

1 Answer
Feb 5, 2017

y=3x+23

Explanation:

The slope-intercept form of a linear equation is: y=mx+b

Where m is the slope and b is the y-intercept value.

We can transform this equation to slope-intercept form by solving for y:

y11=3(x+4)

y11=(3×x)+(3×4)

y11=3x+12

y11+11=3x+12+11

y0=3x+23

y=3x+23