How do you write #y=2/3x^2-4/5x# in vertex form?

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Answer 1 · 2018-02-24T11:02:45

#y=2/3(x-3/5)^2-6/25#

#y = 2/3 x^2 - 4/5 x#

Take out a factor of #2/3#,

#y = 2/3[x^2 - 6/5 x]#

Complete the square,

#y= 2/3[(x-3/5)^2-9/25]#

And multiply out,

#y=2/3(x-3/5)^2-6/25#