How do you write #y= 2x^2 - 8x + 13# into vertex form?

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Answer 1 · 2015-05-22T14:24:23

Vertex form for a quadratic is
#y = m(x-a) +b# where the vertex is #(a,b)#

Given #y=2x^2-8x+13#

Extract #m#

#y= 2(x^2-4x) + 13#

Complete the square

#y= 2(x^2-4x+4) + 13 +8#

Complete writing in vertex form

#y = 2(x-2)^2 +21#