How do you write $y= 2x^2 - 8x + 13$ into vertex form?

Question

7794 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-22T14:24:23

Vertex form for a quadratic is
$y = m(x-a) +b$ where the vertex is $(a,b)$

Given $y=2x^2-8x+13$

Extract $m$

$y= 2(x^2-4x) + 13$

Complete the square

$y= 2(x^2-4x+4) + 13 +8$

Complete writing in vertex form

$y = 2(x-2)^2 +21$

How do you write y= 2x^2 - 8x + 13y= 2x^2 - 8x + 13 into vertex form?