# How do you write y = 3(x+1)^2 - 27 in standard form?

${\left(x + 1\right)}^{2} = \left(x + 1\right) \left(x + 1\right) = {x}^{2} + 2 x + 1$
$y = 3 \left({x}^{2} + 2 x + 1\right) - 27$
$y = 3 {x}^{2} + 6 x + 3 - 27$
$y = 3 {x}^{2} + 6 x - 24$