Question

How do you write `y=3x^2-6x+1` into vertex form?

Answer 1

Vertex form for a quadratic is
`y = m(x-a)+b`
(where `(a,b)` is the vertex)

`y=3x^2-6x+1`

`y=3(x^2-2x)+1 " extracting the "m" constant"`

`y=3(x^2-2x+1) -3 +1 " [completing the square](http://socratic.org/algebra/quadratic-equations-and-functions/completing-the-square-1)"`

`y=3(x-1)^2 -2 " simplification"`

`y=3(x-1)^2+(-2)" into completely vertex form"`