How do you write $y - 6 = \frac{4}{3} (x - 3)$ $y-6=4/3(x-3)$ in standard form?

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Answer 1 · 2018-07-09T22:40:16

$y = \frac{4}{3} x + 2$ $y=4/3x+2$

The given equation of line: $y - 6 = \frac{4}{3} (x - 3)$ $y-6=4/3(x-3)$ can be rewritten in slope intercept form as follows

$y - 6 = \frac{4}{3} x - \frac{4}{3} \cdot 3$ $y-6=4/3x-4/3 \cdot3$

$y = \frac{4}{3} x - 4 + 6$ $y=4/3x-4+6$

$y = \frac{4}{3} x + 2$ $y=4/3x+2$

Answer 2 · 2018-07-09T22:44:04

$y = \frac{4}{3} x + 2$ $y=4/3x+2$

We are essentially trying to get this equation into slope-intercept form, so the only thing we want on the left is a $y$ $y$ .

In our example, we can start by distributing the $\frac{4}{3}$ $4/3$ on the right side to get

$y - 6 = \frac{4}{3} x - 4$ $y-6=4/3x-4$

Next, let's add $6$ $6$ to both sides to get

$y = \frac{4}{3} x + 2$ $y=4/3x+2$

Now, our equation is in slope-intercept form, $y = m x + b$ $y=mx+b$ .

Hope this helps!

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