How do you write $y = (x + 1) (x - 3)$ $y = (x+1)(x-3)$ into vertex form?

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Answer 1 · 2015-05-09T19:42:05

The vertex form is:

$y - y_{v} = a {(x - x_{v})}_{v}^{2}$ $y-y_v=a(x-x_v)^2$ .

So:

$y = (x + 1) (x - 3) \Rightarrow y = x^{2} - 3 x + x - 3 \Rightarrow$ $y=(x+1)(x-3)rArry=x^2-3x+x-3rArr$

$y = x^{2} - 2 x - 3 \Rightarrow y = x^{2} - 2 x + 1 - 1 - 3 \Rightarrow$ $y=x^2-2x-3rArry=x^2-2x+1-1-3rArr$

$y = {(x - 1)}^{2} - 4 \Rightarrow y + 4 = {(x - 1)}^{2}$ $y=(x-1)^2-4rArry+4=(x-1)^2$ .

How do you write y = (x+1)(x-3)y=(x+1)(x−3)y = (x+1)(x-3) into vertex form?