How do you write #y = (x+1)(x-3)# into vertex form? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Massimiliano May 9, 2015 The vertex form is: #y-y_v=a(x-x_v)^2#. So: #y=(x+1)(x-3)rArry=x^2-3x+x-3rArr# #y=x^2-2x-3rArry=x^2-2x+1-1-3rArr# #y=(x-1)^2-4rArry+4=(x-1)^2#. Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 1348 views around the world You can reuse this answer Creative Commons License