# How do you write #y = (x-2)^2 - 16# in standard form?

##### 1 Answer

Jan 4, 2017

#### Explanation:

The standard form of a

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=ax^2+bx+c)color(white)(2/2)|)))# To obtain

#y=(x-2)^2-16" in this form"# expand the brackets and simplify.

#y=(x-2)^2-16=(color(red)(x-2))(x-2)-16#

#=color(red)(x)(x-2)color(red)(-2)(x-2)-16#

#=x^2-2x-2x+4-16# collecting like terms.

#rArry=x^2-4x-12larr" in standard form"#