How do you write #y = (x-2)^2 - 16# in standard form?
1 Answer
Jan 4, 2017
Explanation:
The standard form of a
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=ax^2+bx+c)color(white)(2/2)|)))# To obtain
#y=(x-2)^2-16" in this form"# expand the brackets and simplify.
#y=(x-2)^2-16=(color(red)(x-2))(x-2)-16#
#=color(red)(x)(x-2)color(red)(-2)(x-2)-16#
#=x^2-2x-2x+4-16# collecting like terms.
#rArry=x^2-4x-12larr" in standard form"#