# How many atoms are in 0.40 mol of sulfur?

Feb 15, 2016

In $1$ $m o l$ of stuff, there are $6.022 \times {10}^{23}$ individual items of that stuff.

#### Explanation:

Now sulfur is non-molecular. Given the context of the question, I think I would be perfectly justified in giving the answer as:

${N}_{A}$ $\text{sulfur atoms}$ $\times$ $0.40 \cdot m o l$ $=$ $6.022 \times {10}^{23} \cdot \cancel{m o {l}^{-} 1} \times 0.40 \cdot \cancel{m o l}$ $=$ $2.4 \times {10}^{23}$ individual sulfur atoms.

$\text{how many atoms are in 0.40 mol oxygen?}$,
I would have had to answer $4.8 \times {10}^{23}$ individual oxygen atoms, because it would contain the unstated assumption that oxygen is a binuclear gas, ${O}_{2}$ (note that all the elemental gases, save the Noble Gases, are binuclear). Do you see the distinction I am trying to make?