# How many grams of Ag can be formed from 5.50 grams of Ag_2O in the equation: 2Ag_2O (s) -> 4Ag (s) + O_2 (g)?

Jun 3, 2016

Clearly $\text{moles of silver oxide:moles of dioxygen}$ $=$ $2 : 1$.

#### Explanation:

$\text{Moles of silver oxide}$ $=$ $\frac{5.50 \cdot g}{231.74 \cdot g \cdot m o {l}^{-} 1}$ $=$ ??mol

$\text{Grams of silver metal}$ $=$

$2 \times \frac{5.50 \cdot g}{231.74 \cdot g \cdot m o {l}^{-} 1} \times 107.87 \cdot g \cdot m o {l}^{-} 1$ $=$ ??*g.

Why did I put the $2$ in the front of the expression?