# How many grams of oxygen can be produced by completely decomposing 10 g of mercury(II) oxide?

$2 H g O \left(s\right) + \Delta \rightarrow H g \left(l\right) + {O}_{2} \left(g\right)$
Moles of $H g O$ $=$ $\frac{10 \cdot g}{216.6 \cdot g \cdot m o {l}^{-} 1}$ $=$ $0.0461$ $m o l$.
There are thus $\frac{0.0461 \cdot \cancel{m o l}}{2} \times 32.00 \cdot g \cdot \cancel{m o {l}^{-} 1}$ $\text{dioxygen gas}$ $=$ ??g