How many liters of oxygen are required to react completely with 2.4 liters of hydrogen to form water? #2H_2(g) + O_2(g) -> 2H_2O(g)#?

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Answer 1 · 2017-04-30T20:14:54

Why #1.2*L# precisely..........

Recall old Avogadro's hypothesis...........

#"Equal volumes of gases contain AN EQUAL NUMBER of PARTICLES"#

And thus if there are #2.4*L# of dihydrogen, stoichiometric equivalence requires #1.2*L# of dioxygen. How many litres of water gas result?

Answer 2 · 2017-04-30T20:17:56

#1.2 L#

Know that one mole of any gas at STP takes up 22.4 liters. So 2.4 L of hydrogen is #0.107142857 mols H_2#.

Since #H_2# reacts with #O_2# in a 2:1 ratio, to completely react the two you will need half as much oxygen as hydrogen.

#"mols " O_2= (0.107142857 mols H_2)/2#

#"mols " O_2 = 0.053571429 mols#

To find liters of oxygen, just multiply the moles above by 22.4 liters.

#"liters "O_2 = 0.053571429 mols * 22.4 L/(mols)#

#"liters " O_2 = 1.2L#