How many liters of oxygen are required to react completely with 2.4 liters of hydrogen to form water? 2H_2(g) + O_2(g) -> 2H_2O(g)?

2 Answers
Apr 30, 2017

Why 1.2*L precisely..........

Explanation:

Recall old Avogadro's hypothesis...........

"Equal volumes of gases contain AN EQUAL NUMBER of PARTICLES"

And thus if there are 2.4*L of dihydrogen, stoichiometric equivalence requires 1.2*L of dioxygen. How many litres of water gas result?

Apr 30, 2017

1.2 L

Explanation:

Know that one mole of any gas at STP takes up 22.4 liters. So 2.4 L of hydrogen is 0.107142857 mols H_2.

Since H_2 reacts with O_2 in a 2:1 ratio, to completely react the two you will need half as much oxygen as hydrogen.

"mols " O_2= (0.107142857 mols H_2)/2

"mols " O_2 = 0.053571429 mols

To find liters of oxygen, just multiply the moles above by 22.4 liters.

"liters "O_2 = 0.053571429 mols * 22.4 L/(mols)

"liters " O_2 = 1.2L