How many liters of oxygen gas can be generated at 20.0 C and 0.998 atm by the decomposition of 12.6 g of water?

1 Answer
May 11, 2017

Answer:

Approx....#8.5*L# #"dioxygen gas"#.

Explanation:

We have the decomposition reaction:

#H_2O(g) rarr 1/2O_2(g) + H_2(g)#.

And if there are #(12.6*g)/(18.01*g*mol^-1)#, there are #0.700*mol# water.......

Stoichiometry insists that HALF an equivalent of dioxygen gas can be isolated.......i.e. #0.35*mol#

Given #V=(nRT)/P#, this represents a volume of ...........

#V=(0.35*molxx0.0821*(L*atm)/(K*mol)xx293.15*K)/(0.998*atm)#

#="under 10 L dioxygen gas..........."#