# How many liters of oxygen gas can be generated at 20.0 C and 0.998 atm by the decomposition of 12.6 g of water?

May 11, 2017

Approx....$8.5 \cdot L$ $\text{dioxygen gas}$.

#### Explanation:

We have the decomposition reaction:

${H}_{2} O \left(g\right) \rightarrow \frac{1}{2} {O}_{2} \left(g\right) + {H}_{2} \left(g\right)$.

And if there are $\frac{12.6 \cdot g}{18.01 \cdot g \cdot m o {l}^{-} 1}$, there are $0.700 \cdot m o l$ water.......

Stoichiometry insists that HALF an equivalent of dioxygen gas can be isolated.......i.e. $0.35 \cdot m o l$

Given $V = \frac{n R T}{P}$, this represents a volume of ...........

$V = \frac{0.35 \cdot m o l \times 0.0821 \cdot \frac{L \cdot a t m}{K \cdot m o l} \times 293.15 \cdot K}{0.998 \cdot a t m}$

$= \text{under 10 L dioxygen gas...........}$