How many molecules of oxygen are required to react with 174 g of carbon monoxide in the reaction CO + O_2 -> CO_2?

Jun 9, 2016

The stoichiometrically balanced equation is:

$C O \left(g\right) + \frac{1}{2} {O}_{2} \left(g\right) \rightarrow C {O}_{2} \left(g\right)$

Explanation:

The balanced equation tells us unequivocally that $28 \cdot g$ of carbon monoxide gas reacts with $16 \cdot g$ of dioxygen gas to give $44 \cdot g$ of carbon monoxide. As is the case in ANY chemical reaction, mass is conserved.

So $\text{moles of } C \equiv O$ $=$ $\frac{174 \cdot g}{28 \cdot g \cdot m o {l}^{-} 1}$ $=$ $6.22 \cdot m o l$.

And thus $3.11 \cdot m o l$ dioxygen gas are required, that is $3.11 \cdot m o l \times 6.022 \times {10}^{23} {\text{ molecules mol}}^{-} 1$ $=$ ??" molecules"