How many molecules of water will be produced if 52.6g of pentane are burned?

1 Answer
Jul 4, 2016

Answer:

Approx. #3.5xxN_A#, where #N_A="Avogadro's Number"#

Explanation:

We need (i) a balanced chemical equation:

#C_5H_12(l) + 8O_2(g) rarr 5CO_2(g) + 6H_2O(l)#

And thus for each mole of pentane combusted, (ii) 6 moles of water are produced.

#"Moles of pentane"# #=# #(52.6*g)/(72.15*g*mol^-1)# #=# #0.729*mol#

And thus #5xx0.729*mol# of water are produced after complete combustion. Since in #1# #mol# there are #6.022xx10^23# individual particles, there are how many water molecules?