How many moles of #H_2# are needed to react with .80 mol of #N_2#?

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Answer 1 · 2015-11-12T08:28:58

#"2.4 mol H"_2"# are needed to react with #"0.80 mol N"_2"#.

Balanced Equation

#"N"_2("g")+"3H"_2("g")##rarr##"2NH"_3("g")#

Multiply the #"0.80 mol N"_2"# times the mole ratio between #"H"_2"# and #"N"_2"# so that moles #"N"_2"# cancel, leaving moles #"H"_2"#.

#0.80cancel("mol N"_2)xx(3"mol H"_2)/(1cancel("mol N"_2))="2.4 mol H"_2"#