# How many moles of oxygen are required to completely react with 16.1 grams of magnesium metal according to the equation: 2 Mg(s) + O2(g) → 2 MgO(s) ?

##### 1 Answer

Mar 14, 2016

#### Answer:

#### Explanation:

- Locate
#Mg# in the periodic table and take note of the atomic mass; - Find the number of moles of magnesium by dividing the mass as provided in the problem against the atomic mass of magnesium;

#n Mg=(mass)/(at. mass)#

#n Mg=0.67 mol# - Then, compute the number of moles of
#O_2# needed to completely react with magnesium through conversion method;

#0.67 cancel(mol Mg) # x# (1 mol O_2)/(2 cancel(mol Mg))# - Make sure to cancel out units that are not needed leaving only the desired units;
- The final answer is found to be
#0.33# moles of#O_2#