How many orbitals make up the 4d subshell?
1 Answer
The same number that makes up any individual
#color(white)(.)ul(l" "" ""shape")#
#color(white)(.)0" "" "s#
#color(white)(.)1" "" "p#
#color(white)(.)2" "" "d#
#color(white)(.)3" "" "f#
#color(white)(.)4" "" "g#
#vdots" "" "vdots#
#m_l = {-l, -l+1, . . . , 0, . . . , l-1, l}#
You can see that there is an odd number of
Since
#2(2) + 1 = bb"five"# #d# orbitals exist in one#d# subshell of any#n# .
And these orbitals are each given one value of