How much 0.05 M HCl solution can be made by diluting 250 mL of 10 M HCl?

1 Answer
anor277
Feb 6, 2016

Calculate the number of MOLES of #HCl# in the starting material. The second volume of solution depends on this molar quantity.

Explanation:

So, there #250xx10^-3cancelLxx 10*mol*Lcancel(""^-1)# #=# #250xx10^-2# #mol# #HCl#.

Concentration #=# #n/V# #=# #"Moles of solute"/"Volume of solution"#

We have the required concentration, #0.05# #mol*L^-1#. So....

#V=n/C# #=# #(250xx10^-2*cancel(mol))/(0.05*cancel(mol)*L^-1)# #=# #??L#

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