Question

How much ammonia (NH3) can be obtained when 3.0g H2 reacts with 100.g N2?

Answer 1

`N_2(g) + 3H_2(g) rarr 2NH_3(g)`

Explanation:

We have the stoichiometric equation above. Clearly, the limiting reagent is dihydrogen gas, as we have only `(3.0*cancel(g))/(2*cancel(g)*mol^(-1))` `=` `??` `mol`.