How would you calculate the number of grams of sodium oxide, Na2O, that will be produced when 5.00 moles react with oxygen given the reaction: 4Na + O2--> 2 Na2O?

1 Answer
Nov 1, 2015

Answer:

#4Na + O_2 rarr 2Na_2O#.

By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol #Na_2O# should result.

Explanation:

The molecular mass of natrium oxide is #61.98# #g*mol^(-1)#. If #5# #mol# natrium react, then #5/2# #molxx61.98# #g*mol^(-1)# #=# #154.95# #g# natrium oxide should result.

So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go.