Question

How would you calculate the number of grams of sodium oxide, Na2O, that will be produced when 5.00 moles react with oxygen given the reaction: 4Na + O2--> 2 Na2O?

Answer 1

`4Na + O_2 rarr 2Na_2O`.

By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol `Na_2O` should result.

Explanation:

The molecular mass of natrium oxide is `61.98` `g*mol^(-1)`. If `5` `mol` natrium react, then `5/2` `molxx61.98` `g*mol^(-1)` `=` `154.95` `g` natrium oxide should result.

So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go.