I have 6 faces, 8 vertices, and 12 edges. Which figure am l?

1 Answer
Jan 1, 2017

It is a cuboid or quadrilaterally-faced hexahedron.

Explanation:

There is no unique formula for getting the figure. However, according to Euler's Polyhedral Formula, in a convex polyhedra, if #V# is the number of vertices, #F# is number of faces and #E# is number of edges than #V-E+F=2#.

It is apparent that with #6# faces, #8# vertices, and #12# edges, then #8-12+6=2#, hence it is a valid polyhedra.

However, it is evident that the figure is a cuboid or quadrilaterally-faced hexahedron, as it too has #6# faces, #8# vertices, and #12# edges.
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