If (-1, y) lies on the graph of y = 3^x+1, then what is y?

Dec 9, 2015

it depend on what the original question is
if $y = {3}^{x} + 1$ , then solution is $\left(- 1 , \frac{4}{3}\right)$

If $y = {3}^{x + 1}$ , then solution is $\left(- 1 , 1\right)$

Explanation:

If the point $\left(- 1 , y\right)$ lies on the graph $y = {3}^{x} + 1$ then what is $y$

We are given $x = - 1$ , and the $y = {3}^{x} + 1$ ; let substitute $- 1$ for $x$ into the equation

$y = {3}^{- 1} + 1$
$y = \frac{1}{3} + 1$
$y = \frac{1}{3} + \frac{3}{3}$
$y = \frac{4}{3}$

The point is $\left(- 1 , \frac{4}{3}\right)$

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If the point $\left(- 1 , y\right)$ lies on the graph of $y = {3}^{x + 1}$, then what is $y$?
Substitute $- 1$ for $x$ into the given equation
$y = {3}^{- 1 + 1}$
$y = {3}^{0}$
$y = 1$
The point is $\left(- 1 , 1\right)$