# If 12 L of a gas at room temperature exerts a pressure of 4 kPa on its container, what pressure will the gas exert if the container's volume changes to 7 L?

Pressure of gas will be $6.857$ kPa.
As at constant temperature, if Pressure is $P$) and Volume is $V$, their product i.e. $P \cdot V$ is always constant.
Here 12L of a gas at room temperature exerts a pressure of 4kPa. Hence their multiplication is 48 and if container's volume changes to 7L. pressure of gas exerted on container will become $\frac{48}{7} = 6.857$ kPa.