Question

If a projectile is shot at an angle of `(2pi)/3` and at a velocity of `23 m/s`, when will it reach its maximum height?

Answer 1

`t=2,03 " s"`

Explanation:

`" you can use the formula "t=(v_i*sin alpha)/g`

`v_i=23 m/s`

`alpha=(2pi)/3`

`g=9,81`

`t=(23*sin((2pi)/3))/(9,81)`

`t=2,03 " s"`