# If a projectile is shot at an angle of pi/2 and at a velocity of 17 m/s, when will it reach its maximum height??

Dec 27, 2015

After $1.73 \text{s}$

#### Explanation:

The launch angle = $\frac{\pi}{2}$ radians which is ${90}^{\circ}$ which means a vertical launch.

$v = u + a t$

This becomes:

$0 = u - \text{g} t$

$\therefore 0 = 17 - 9.8 t$

$\therefore t = \frac{17}{9.8} = 1.73 \text{s}$