If a projectile is shot at an angle of pi/2 and at a velocity of 22 m/s, when will it reach its maximum height??

Oct 22, 2016

I got: $2.2 s$

Explanation:

If I interpreted it right, the bullet is shot perfectly vertically and will reach its maximum height where its final velocity ${v}_{f}$ will be zero.
We can use kinematics in the form of the relationship:
${v}_{f} = {v}_{i} + a t$
where the acceleration $a$ will be acceleration of gravity $g = 9.8 \frac{m}{s} ^ 2$ directed downwards (and so it will have a negative sign).
We get:
$0 = 22 - 9.8 t$
rearranging:
$t = \frac{22}{9.8} = 2.2 s$