If a projectile is shot at an angle of #pi/2# and at a velocity of #37 m/s#, when will it reach its maximum height??

1 Answer
Jan 5, 2017

Answer:

We need to find the instant at which the projectile's vertical component of velocity is zero.

Explanation:

The vertical component of the velocity at time #t# is given by #v(t)=u-g t#, where #u# is the projectile's initial vertical component of velocity and #g# is the gravitational acceleration constant.

So we are required to solve #0=u-g t#, which gives #t=u/g#

Now, #u=37 sin (pi/2)#m/s and we take #g=10mbox{}#m/s#\mbox{}^2#. So the final answer is #t=37/10=3.7#s.