Question

If a projectile is shot at an angle of `pi/2` and at a velocity of `37 m/s`, when will it reach its maximum height??

Answer 1

We need to find the instant at which the projectile's vertical component of velocity is zero.

Explanation:

The vertical component of the velocity at time `t` is given by `v(t)=u-g t`, where `u` is the projectile's initial vertical component of velocity and `g` is the gravitational acceleration constant.

So we are required to solve `0=u-g t`, which gives `t=u/g`

Now, `u=37 sin (pi/2)`m/s and we take `g=10mbox{}`m/s`\mbox{}^2`. So the final answer is `t=37/10=3.7`s.