# If a projectile is shot at an angle of (pi)/8 and at a velocity of 95 m/s, when will it reach its maximum height?

Mar 5, 2016

$t \cong 3 , 71 \text{ } s$
$t = {v}_{i} \cdot \sin \frac{\alpha}{g} \text{ elapsed time to maximum height:}$
$t = \frac{95 \cdot \sin 22 , 5}{9 , 81}$
$t \cong 3 , 71 \text{ } s$