# If a sample of 4 moles of gas has a pressure of 567.42 kPa and a volume of 12.0 L, what is its temperature?

##### 1 Answer
Feb 20, 2016

Its temperature is -68 °C.

To answer this question, we can use the Ideal Gas Law:

$P V = n R T$

$P = \text{567.42 kPa;"color(white)(m) V = "12.0 L;"color(white)(m) n = "4 mol;" color(white)(m)R = "8.314 kPa·L·K"^"-1""mol"^"-1}$

T = (PV)/(nR) = (567.42 color(red)(cancel(color(black)("kPa"))) × 12.0 color(red)(cancel(color(black)("L"))))/(4 color(red)(cancel(color(black)("mol"))) × 8.314 color(red)(cancel(color(black)("kPa·L")))·"K"^"-1"color(red)(cancel(color(black)("mol"^"-1")))) = "205 K" = "-68 °C"

The temperature of the gas is -68 °C.