# If a sample of oxygen gas has a pressure of 810 torr at 298 K, what will be its pressure if its temperature is raised to 330 K?

Dec 27, 2016

The pressure is $= 897$torr

#### Explanation:

We use Gay Lussac's Law

${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$

${P}_{1} = 810$torr

${T}_{1} = 298 K$

${T}_{2} = 330 K$

${P}_{2} = {P}_{1} / {T}_{1} \cdot {T}_{2} = \frac{810}{298} \cdot 330 = 897$ torr