If a spring has a constant of #4 (kg)/s^2#, how much work will it take to extend the spring by #63 cm #?

1 Answer
Feb 16, 2017

Answer:

I got #0.8J#

Explanation:

We will need to do work #W# to extend the spring that, as a result, will acquire an Elastic Potential Energy equal to #1/2kx^2#:
so, the energy we put to extend the spring (as work) will be converted into potential energy and so for our system:
#W=1/2kx^2#
or (using meters for the elongation):
#W=1/2*4*(0.63)^2=0.7939~~0.8J#