# If an alloy containing 30% zinc is mixed with a 55 % zinc alloy to get 800 pounds of 40% alloy, how much of each must be used?

Aug 25, 2015

Have a look if it makes sense...

#### Explanation:

I considered quantities of Zinc in each alloy and the final amount as:

Where $x$ and $y$ are the quantities in pounds of alloy 1 and 2.
Solving the system I got:
$x = 4.8 \text{pounds}$ of alloy 1
$y = 3.2 \text{pounds}$ of alloy 2