# If an equilateral triangle has a height of 4.7sqrt3 and base of 9.4 cm, what is its area?

$\frac{1}{2} \times b a s e \times h e i g h t = {4.7}^{2} \sqrt{3}$ $c {m}^{2}$
$= 22.09 \sqrt{3}$ $c {m}^{2}$
$\cong 38.261$ $c {m}^{2}$