If an object is moving at #1 m/s# over a surface with a kinetic friction coefficient of #u_k=5 /g#, how far will the object continue to move?

1 Answer
Jun 8, 2018

Answer:

0,1 m

Explanation:

The friction force that opposite to the movement is
#F= mu_k xx m xx g=5 m#
the deceletaion given by the friction force, from the second dynamic law is:
#a= F/m= 5 m/m = 5m/s^2#
from the movement law
#v = a xx t #
you have
#t= v/a = (1 m/s )/(5 m/s^2)= 0,2 s#
and
#s = v° xx t - 1/2 a xx t^2 = 1m/s xx 0,2 s -0.5 xx5 m/s^2 xx (0.2 s)^2= 0,2 m-0,1 m = 0,1 m#