# If an object is moving at 10 m/s over a surface with a kinetic friction coefficient of u_k=2 /g, how far will the object continue to move?

Mar 20, 2018

$\text{25 m}$

#### Explanation:

Acceleration of object = -μ_k"g" = -2/cancel("g") × cancel("g") = -"2 m/s"^2

"S" = -("u"^2)/(2a) color(white)(....)[∵ "v" = 0]

$\text{S" = -(("10 m/s")^2)/(2 × (-"2 m/s"^2)) = "25 m}$