If an object is moving at #10 m/s# over a surface with a kinetic friction coefficient of #u_k=2 /g#, how far will the object continue to move?

1 Answer
Mar 20, 2018

Answer:

#"25 m"#

Explanation:

Acceleration of object #= -μ_k"g" = -2/cancel("g") × cancel("g") = -"2 m/s"^2#

#"S" = -("u"^2)/(2a) color(white)(....)[∵ "v" = 0]#

#"S" = -(("10 m/s")^2)/(2 × (-"2 m/s"^2)) = "25 m"#