If an object is moving at #150 m/s# over a surface with a kinetic friction coefficient of #u_k=2250 /g#, how far will the object continue to move? Physics Forces and Newton's Laws Frictional Forces 1 Answer ali ergin May 28, 2016 #Delta x=5 m# Explanation: #v_i=150 m/s" initial velocity"# #u_k=2250/g" coefficient of friction"# #"The object is decreased by the friction force"# #F_f=u_k*m*g" # #F_f=2250/cancel(g)*m*cancel(g)# #F=m*a# #2250*cancel(m)=cancel(m)*a# #a=2250" " m/s^2# #v_f^2=v_i^2-2*a*Delta x# #"the final velocity of object will be zero if object stops." # #0=v_i^2-2*a*Delta x# #Delta x=v_i^2/(2*a)# #Delta x=150^2/(2250)# #Delta x=22500/(2*2250)# #Delta x=5 m# Answer link Related questions Question #d6539 Question #242b7 Question #6bde4 Question #50c79 Question #a2018 Question #f7a62 Question #27931 Question #0b375 Question #d70af Question #dab6f See all questions in Frictional Forces Impact of this question 1374 views around the world You can reuse this answer Creative Commons License