If an object is moving at #150 m/s# over a surface with a kinetic friction coefficient of #u_k=2250 /g#, how far will the object continue to move?

1 Answer
May 28, 2016

Answer:

#Delta x=5 m#

Explanation:

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#v_i=150 m/s" initial velocity"#
#u_k=2250/g" coefficient of friction"#

#"The object is decreased by the friction force"#

#F_f=u_k*m*g" #

#F_f=2250/cancel(g)*m*cancel(g)#

#F=m*a#

#2250*cancel(m)=cancel(m)*a#

#a=2250" " m/s^2#

#v_f^2=v_i^2-2*a*Delta x#

#"the final velocity of object will be zero if object stops." #

#0=v_i^2-2*a*Delta x#

#Delta x=v_i^2/(2*a)#

#Delta x=150^2/(2250)#

#Delta x=22500/(2*2250)#

#Delta x=5 m#