If I inhale 2.20 L of gas at a temperature of 18°C at a pressure of 1.50 atm, how many moles of gas were inhaled?

1 Answer
Oct 1, 2016

#n="0.138 mol"#

Explanation:

You will need the ideal gas law to answer this question. The formula for the ideal gas law is:
https://jahschem.wikispaces.com/ideal+gas+law

Known
#P="1.50 atm"#
#V="2.20 L"#
#R="0.082057338 L atm K"^(-1) "mol"^(-1)"#
#T="18"^@"C"+"273.15 K=291 K"#

Unknown
#n#

Solution
Rearrange the formula to isolate #n#. Substitute the known values into the formula and solve.

#n=(PV)/(RT)#

#n=(1.50cancel"atm"xx2.20cancel"L")/(0.082057338cancel"L" cancel"atm" cancel"K"^(-1) "mol"^(-1)xx291cancel"K")="0.138 mol"#