# If I inhale 2.20 L of gas at a temperature of 18°C at a pressure of 1.50 atm, how many moles of gas were inhaled?

Oct 1, 2016

$n = \text{0.138 mol}$

#### Explanation:

You will need the ideal gas law to answer this question. The formula for the ideal gas law is:

Known
$P = \text{1.50 atm}$
$V = \text{2.20 L}$
$R = \text{0.082057338 L atm K"^(-1) "mol"^(-1)}$
$T = \text{18"^@"C"+"273.15 K=291 K}$

Unknown
$n$

Solution
Rearrange the formula to isolate $n$. Substitute the known values into the formula and solve.

$n = \frac{P V}{R T}$

n=(1.50cancel"atm"xx2.20cancel"L")/(0.082057338cancel"L" cancel"atm" cancel"K"^(-1) "mol"^(-1)xx291cancel"K")="0.138 mol"