Question

If iron (II) oxide gas decomposes into iron liquid and oxygen gas and 6 moles of iron (II) oxide gas are used, how of liters of oxygen gas are produced?

Answer 1

The reaction equation is: `2FeO->2Fe+O_2`

Explanation:

This means that for `6mol` of `FeO`, only `3mol O_2` is produced (half the moles).
The volume of the oxygen is dependant on temperature and pressure.

E.g. : If you cooled it down to `0^oC` and get it to standard atmospheric pressure the volume would be `3*22.4L=67.2L`
The 22.4 L being the molar volume for ideal gases under those conditions. There are tables for other temperatures.