# If sides A and B of a triangle have lengths of 1 and 6 respectively, and the angle between them is (7pi)/8, then what is the area of the triangle?

$\text{Area of the triangle} = \frac{1}{2} A B \sin \left(7 \frac{\pi}{8}\right)$
$= \frac{1}{2} \cdot 1 \cdot 6 \cdot \sin \left(\pi - \frac{\pi}{8}\right)$
$= 3 \cdot \sin \left(\frac{\pi}{8}\right) = 1.148 s q u n i t$