# If sides A and B of a triangle have lengths of 2 and 7 respectively, and the angle between them is (pi)/8, then what is the area of the triangle?

Mar 22, 2016

≈ 2.679 square units

#### Explanation:

Given a triangle with 2 sides and the angle between them known , as in this question then we can use the following formula.

area $= \frac{1}{2} a b \sin \theta$

where a and b are the 2 sides and $\theta , \text{ the angle between them }$

here a = 2 , b = 7 and $\theta = \frac{\pi}{8}$

$\Rightarrow \text{ area " = 1/2xx2xx7xxsin(pi/8) ≈ 2.679" square units }$