# If sides A and B of a triangle have lengths of 4 and 2 respectively, and the angle between them is (7pi)/12, then what is the area of the triangle?

Jan 24, 2016

3.86 square units

#### Explanation:

When given 2 sides and the angle between them, of a triangle.

the formula ; $A = \frac{1}{2} a b \sin \theta$

where a and b are length of sides and $\theta$ the angle between
them, will enable the area to be calculated.

here a = 4 , b = 2 and $\theta = \frac{7 \pi}{12}$

$\Rightarrow A = \frac{1}{2} \times 4 \times 2 \times \sin \left(\frac{7 \pi}{12}\right) = 3.86$