# If sides A and B of a triangle have lengths of 8 and 6 respectively, and the angle between them is (7pi)/8, then what is the area of the triangle?

Feb 11, 2016

≈ 9.84 square units

#### Explanation:

Given a triangle with 2 sides and the angle between them known the area of the triangle can be calculated using :

$a r e a = \frac{1}{2} A B \sin \theta$

where $\theta \textcolor{b l a c k}{\text{ is the angle between the 2 sides }}$

here A = 8 , B = 6 and $\theta = \frac{7 \pi}{8}$

hence area =  1/2 xx 8 xx 6 xx sin((7pi)/8) ≈9.84