If the angle $(29pi)/6$ is in standard position, which quadrant does it terminate?

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Answer 1 · 2016-11-26T17:03:05

This angle ends in the second quadrant. See explanation.

First we have to change the fraction in the angle to a mixed number:

$(29pi)/6=4 5/6pi=4pi+(5pi)/6$

Adding a multiple of $2pi$ does not change the end quadrant, so $(29pi)/6$ lies in the same quadrant as $(5pi)/6$

$pi/2 <= (5pi)/6 <=pi$ , so this angle lies in the second quadrant.

If the angle (29pi)/6(29pi)/6 is in standard position, which quadrant does it terminate?