# If the initial of an ideal gas at 2.250 atm is 62.00°c, what final temperature would cause the pressure to be reduced to 1.750 atm?

Jun 2, 2018

$\text{260.5 K}$

#### Explanation:

From Gay Lussac’s Law

$\textcolor{w h i t e}{\ldots} \text{P ∝ T}$

${\text{P"_1/"T"_1 = "P"_2/"T}}_{2}$

${\text{T"_2 = "P"_2 × "T"_1/"P}}_{1}$

$\textcolor{w h i t e}{\text{T"_2) = 1.750 cancel"atm" × "(62.00 + 273) K"/(2.250 cancel"atm}}$

color(white)("T"_2) = 1.750 × "335 K"/2.250

color(white)("T"_2) = 260.5\ "K"